The diagonal object of a morphism. #
We provide various API and isomorphisms considering the diagonal object Δ_{Y/X} := pullback f f
of a morphism f : X ⟶ Y.
The diagonal object of a morphism f : X ⟶ Y is Δ_{X/Y} := pullback f f.
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The diagonal morphism X ⟶ Δ_{X/Y} for a morphism f : X ⟶ Y.
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The two projections Δ_{X/Y} ⟶ X form a kernel pair for f : X ⟶ Y.
The underlying map of pullbackDiagonalIso
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The underlying inverse of pullbackDiagonalIso
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This iso witnesses the fact that
given f : X ⟶ Y, i : U ⟶ Y, and i₁ : V₁ ⟶ X ×[Y] U, i₂ : V₂ ⟶ X ×[Y] U, the diagram
V₁ ×[X ×[Y] U] V₂ ⟶ V₁ ×[U] V₂
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↓ ↓
X ⟶ X ×[Y] X
is a pullback square.
Also see pullback_fst_map_snd_isPullback.
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This iso witnesses the fact that
given f : X ⟶ T, g : Y ⟶ T, and i : T ⟶ S, the diagram
X ×ₜ Y ⟶ X ×ₛ Y
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↓ ↓
T ⟶ T ×ₛ T
is a pullback square.
Also see pullback_map_diagonal_isPullback.
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The diagonal object of X ×[Z] Y ⟶ X is isomorphic to Δ_{Y/Z} ×[Z] X.
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Informally, this is a special case of pullback_map_diagonal_isPullback for T = X.
Given the following diagram with S ⟶ S' a monomorphism,
X ⟶ X'
↘ ↘
S ⟶ S'
↗ ↗
Y ⟶ Y'
This iso witnesses the fact that
X ×[S] Y ⟶ (X' ×[S'] Y') ×[Y'] Y
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↓ ↓
(X' ×[S'] Y') ×[X'] X ⟶ X' ×[S'] Y'
is a pullback square. The diagonal map of this square is pullback.map.
Also see pullback_lift_map_is_pullback.
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