Basic theorems about ℒp space #
f : α → ℝ and ENNReal.ofReal ∘ f : α → ℝ≥0∞ have the same eLpNorm.
Usually, you should not use this lemma (but use enorms everywhere.)
Alias of MeasureTheory.MemLp.of_le.
For a function f with support in s, the Lᵖ norms of f with respect to μ and
μ.restrict s are the same.
See eLpNorm_smul_measure_of_ne_zero' for a version with scalar multiplication by ℝ≥0.
See eLpNorm_smul_measure_of_ne_zero for a version with scalar multiplication by ℝ≥0∞.
See eLpNorm_smul_measure_of_ne_top' for a version with scalar multiplication by ℝ≥0.
See eLpNorm_smul_measure_of_ne_top' for a version with scalar multiplication by ℝ≥0∞.
Alias of MeasureTheory.enorm_ae_le_eLpNormEssSup.
If ‖f x‖ₑ ≤ c * ‖g x‖ₑ a.e., eLpNorm' f p μ ≤ c * eLpNorm' g p μ for all p ∈ (0, ∞).
When c is negative, ‖f x‖ ≤ c * ‖g x‖ is nonsense and forces both f and g to have an
eLpNorm of 0.
If ‖f x‖ₑ ≤ c * ‖g x‖ₑ, then eLpNorm f p μ ≤ c * eLpNorm g p μ.
This version assumes c is finite, but requires no measurability hypothesis on g.
If ‖f x‖ₑ ≤ c * ‖g x‖ₑ, then eLpNorm f p μ ≤ c * eLpNorm g p μ.
This version allows c = ∞, but requires g to be a.e. strongly measurable.
Bounded actions by normed rings #
In this section we show inequalities on the norm.
Bounded actions by normed division rings #
The inequalities in the previous section are now tight.
TODO: do these results hold for any NormedRing assuming NormSMulClass?
A continuous function with compact support belongs to L^∞.
See Continuous.memLp_of_hasCompactSupport for a version for L^p.
A single function that is MemLp f p μ is tight with respect to μ.