Bilinear form and linear maps #
This file describes the relation between bilinear forms and linear maps.
TODO #
A lot of this file is now redundant following the replacement of the dedicated _root_.BilinForm
structure with LinearMap.BilinForm, which is just an alias for M →ₗ[R] M →ₗ[R] R. For example
LinearMap.BilinForm.toLinHom is now just the identity map. This redundant code should be removed.
Notation #
Given any term B of type BilinForm, due to a coercion, can use
the notation B x y to refer to the function field, i.e. B x y = B.bilin x y.
In this file we use the following type variables:
M,M', ... are modules over the commutative semiringR,M₁,M₁', ... are modules over the commutative ringR₁,V, ... is a vector space over the fieldK.
References #
Tags #
Bilinear form,
Auxiliary definition to define toLinHom; see below.
Equations
- A.toLinHomAux₁ x = A x
Instances For
The linear map obtained from a BilinForm by fixing the right co-ordinate and evaluating in
the left.
Instances For
Apply a linear map on the output of a bilinear form.
Equations
- f.compBilinForm B = (LinearMap.restrictScalars₁₂ R' R' B).compr₂ f
Instances For
Apply a linear map on the left and right argument of a bilinear form.
Equations
- B.comp l r = LinearMap.compl₁₂ B l r
Instances For
Apply a linear map to the left argument of a bilinear form.
Equations
- B.compLeft f = B.comp f LinearMap.id
Instances For
Apply a linear map to the right argument of a bilinear form.
Equations
- B.compRight f = B.comp LinearMap.id f
Instances For
Apply a linear equivalence on the arguments of a bilinear form.
Equations
- LinearMap.BilinForm.congr e = (LinearEquiv.congrLeft R R e).congrRight.trans (LinearEquiv.congrLeft (M' →ₗ[R] R) R e)
Instances For
When N₁ and N₂ are equivalent, bilinear maps on M into N₁ are equivalent to bilinear
maps into N₂.
Equations
Instances For
linMulLin f g is the bilinear form mapping x and y to f x * g y
Equations
- LinearMap.BilinForm.linMulLin f g = (LinearMap.mul R R).compl₁₂ f g
Instances For
Two bilinear forms are equal when they are equal on all basis vectors.
Write out B x y as a sum over B (b i) (b j) if b is a basis.