Bases of submodules #
If the submodule P has a basis, x ∈ P iff it is a linear combination of basis vectors.
If the submodule P has a finite basis,
x ∈ P iff it is a linear combination of basis vectors.
If N is a submodule with finite rank, do induction on adjoining a linear independent
element to a submodule.
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- One or more equations did not get rendered due to their size.
Instances For
An element of a non-unital-non-associative algebra is in the center exactly when it commutes with the basis elements.
Let b be an S-basis of M. Let R be a CommRing such that Algebra R S has no zero smul
divisors, then the submodule of M spanned by b over R admits b as an R-basis.
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Instances For
Let b be an S-basis of M. Then m : M lies in the R-module spanned by b iff all the
coordinates of m on the basis b are in R (see Basis.mem_span for the case R = S).
Let A be an subgroup of an additive commutative group M that is also an R-module.
Construct a basis of A as a ℤ-basis from a R-basis of E that generates A.
Equations
- Module.Basis.addSubgroupOfClosure A b h = (Module.Basis.restrictScalars ℤ b).map (LinearEquiv.ofEq (Submodule.span ℤ (Set.range ⇑b)) (AddSubgroup.toIntSubmodule A) ⋯)